| #include <algorithm> |
| #include <iostream> |
| #include <tuple> |
| #include <utility> |
| #include <vector> |
| using namespace std; |
|
|
| const int LIM = 1000002; |
|
|
| struct UnionFind { |
| int N; |
| vector<int> root, rank; |
| vector<bool> hasR; |
|
|
| UnionFind(int _N): N(_N), root(_N), rank(_N, 0), hasR(_N, false) { |
| for (int i = 0; i < N; i++) { |
| root[i] = i; |
| } |
| } |
|
|
| int find(int i) { |
| if (root[i] != i) { |
| root[i] = find(root[i]); |
| } |
| return root[i]; |
| } |
|
|
| void merge(int i, int j) { |
| i = find(i); |
| j = find(j); |
| if (i == j) { |
| return; |
| } |
| if (rank[i] > rank[j]) { |
| swap(i, j); |
| } |
| root[i] = j; |
| hasR[j] = hasR[j] || hasR[i]; |
| if (rank[i] == rank[j]) { |
| rank[j]++; |
| } |
| } |
| }; |
|
|
| int R, C, N; |
| int H[LIM]; |
| vector<tuple<int, int, int>> A; |
|
|
| pair<int, int> solve() { |
| A.clear(); |
| |
| cin >> R >> C; |
| N = R * C; |
| for (int i = 0, j; i < N; i++) { |
| cin >> H[i]; |
| if ((j = i - C) >= 0) { |
| A.emplace_back(-min(H[i], H[j]), i, j); |
| } |
| if (i % C > 0 && (j = i - 1) >= 0) { |
| A.emplace_back(-min(H[i], H[j]), i, j); |
| } |
| } |
| for (int i = 0, s; i < N; i++) { |
| cin >> s; |
| A.emplace_back(-s, -1, i); |
| } |
| |
| UnionFind U(N); |
| sort(A.begin(), A.end()); |
| pair<int, int> ans{0, 0}; |
| for (const auto &t : A) { |
| int h = -get<0>(t), a = get<1>(t), b = get<2>(t); |
| if (a < 0) { |
| if (H[b] <= h) { |
| continue; |
| } |
| ans.first++; |
| b = U.find(b); |
| if (!U.hasR[b]) { |
| U.hasR[b] = true; |
| ans.second++; |
| } |
| continue; |
| } |
| U.merge(a, b); |
| } |
| return ans; |
| } |
|
|
| int main() { |
| int T; |
| cin >> T; |
| for (int t = 1; t <= T; t++) { |
| auto ans = solve(); |
| cout << "Case #" << t << ": " << ans.first << " " << ans.second << endl; |
| } |
| return 0; |
| } |
|
|